Simple question about free fall
 

Would the equation of where an object would be in free fall be:

-4.9X^2+C?

Where X is time and C is the height the object begins free fall?

http://www.mathpages.com/rr/s4-03/4-03.htm

this has a bunch of equations, but i dont know if they will help...

i would think that you have to factor in the weight of the object falling...

Well, we are assuming that there are no forces other than gravity acting on the object. In that case, the weight of the object is irrelevant. Thanks for the link, though. I'll check it out.

Holy unholy fuck, I can't understand any of that. A little over my head. Thanks for the link, though.

Wouldn't it just be -9.88X ?
Where 9.8m/s is the speed of gravity and X would be the weight, if this confuses you just skip it. I am trying to think back, what are you looking for?

That site is hard to comprehend.

Gravity is actually 9.8 m/s/s. That's acceleration, not velocity. Weight is irrelevant. Velocity increases at a linear rate, so I'm guessing that displacement would be at a quadratic rate in this scenario.

Try This http://www.glenbrook.k12.il.us/gbssc...Kin/U1L6c.html

Thanks D3V. That's what I was looking for. It's the 1st equation there.