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deadlock75

2004-10-15 09:35 PM

C programming Count uppercase letters in a sentence

I don't know where to start or how to write the program I need some help I am trying to program an uppercase character is an character whose ASCII value is between 65(A) and 90(Z). I need to write a program that prompts the user to enter a string from the keyboard and will count the number uppercase character and replace each uppercase character by the corresponding lowercase character.

Demosthenes

2004-10-16 05:41 AM

Quote:

Originally Posted by deadlock75

PHP Code:


		
			
#include <stdio.h>



int main(void)

{

     char string[50];

     gets(string);

     int count = 0;

     int i;

     for(i = 0; string[i]; i++)

     {

          if(string[i] >= 'A' && string[i] <= 'Z')     

          {

               count++;

          }

     }



     printf("%d", count);

}

WetWired

2004-10-16 11:55 AM

Actually, it would be
for(i=0;i<strlen(string);i++)
not
for(i=0;i<string[i];i++)

Demosthenes

2004-10-16 11:56 AM

Quote:

Originally Posted by WetWired

Actually, it would be
for(i=0;i<strlen(string);i++)
not
for(i=0;i<string[i];i++)

Actually, I don't even know why I did

Code:

i<string[i]

I meant to just say

Code:

string[i]

I'll go ahead and change that.

But yea, WW's method is better. Use strlen.

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