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Posted 2002-11-12, 03:00 PM
in reply to LordZpider's post "Calculus: Related rates"
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Had an epiphany. You do have to use derivatives, and it is quite simple if you know how.
Area of Cone: (1/3)*(pi)*(r)^3
Take the derivative with respect to time:
dAC/dt = (pi)*(r)^2*(dr/dt)
Look at what is known:
dAC/dt is 10 cu ft.
r is cubed root of (3000/pi) as previously found.
Solve for (dr/dt) which is the change in radius with respect to time.
dr/dt = .0328248340614
 There's your answer.
D3V said:
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