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Math Problem, Zelaron Come Together
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Posted 2004-11-18, 04:42 PM in reply to
Shining Knights
's post starting
"It matters not whether you win or lose;..."
*sigh*
x + y = 3 ; 2x + y = 5
Either solve for a variable, plug it in the other equation, and find the value of that variable, or add or subtract the equations from each other. There is no other way to work the problem (besides variations and maps... ex: graph)
Solve for Var:
x + y = 3 --> y = 3 - x
2x + y = 5 = 2x + (3 - x) = x + 3 = 5 --> x = 2
x + y = 3 = 2 + y --> y = 1
Subtract:
x + y - (2x + y) = 3 - 5 = -2 = -x --> x = 2
x + y = 3 = 2 + y --> y = 1
Simple as 3.14159
*sigh* I hate puns...
D3V said:
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