Math Problem, Zelaron Come Together

It matters not whether you win or lose; what matters is whether I win or lose.

well, my friend has said, if cant be done any other way. And i would LOVE to prove him wrong. And who knows, maybe if by finding another way will solve something else.

It can be done by matrices, let me go dig up my algebra notebook because I seem to have forgotten how..

Ah nevermind I remembered:

So x+y=3 and 2x+y=5. Matrix is [1 1 3] [2 1 5] now mR1(-2)+R2 (multiply row 1 by -2 {the inverse of 2} and add the results to row 2) You end up with: [1 1 3] [0 -1 -1] now mR2(1) + R1, you get: [1 0 2] [0 -1 -1] now mR2(-1) to get: [1 0 2] [0 1 1] Row 1: x=2 Row 2: y=1 Done.

This is just one of the matrix methods I learned. A couple are easier, one is a bitch load harder. Also, you can do this on your calculator in 3 seconds.

That doesn't have a damn thing to do with matricies.

You simply organized the numbers into columns and rows, and did the exact same thing I did before, which was add or subtract the equations.

That doesn't have a damn thing to do with matricies. You simply organized the numbers into columns and rows, and did the exact same thing I did before, which was add or subtract the equations.

Well to be fair I didn't read what you did

And it is a matrix because it's in standard matrix gaussian form (or whatever the fuck it's called). There are other methods that involve adding and subtracting matrices also that work, but they're more annoying to do.

Yes, but if you put y before x in the second equation, it doesn't work anymore... It's just manipulating the numbers with brackets around them.

Yes, but if you put y before x in the second equation, it doesn't work anymore... It's just manipulating the numbers with brackets around them.

Part of the pre-requisites are that the equations be in standard form. The same method works with every system of equation, so it's a valid approach.