Solve for X

back from class, here's solution...

#5
(x+y)/(x-y)=2xy
long division
1 + (2y/(x-y))=2xy
multiply everything by (x-y)

HANG ON

then you seperate stuff and quadratic, i'll finish it later

Well shit, now I'm fucking pissed.... Well, I was in my night class, bored as usual, so I decided to tackle that 5th equation. Well, as it turns out, I did the wrong equation, but the process still works for this one, which I will not do at this time again.... Alright, I'll admit, I did kinda cheat.... Chruser said that is had to be turned into a fourth order polynomial, so with that in mind:

That's really close Titus, it's not entirely correct, but that's definitely on the right track. That solution was scarily long too.

Bah, I guess I'll work on the right equation today. And yes, it is scarily long...

This is what my symbolic solver gives me:

inside the square root, are you sure it's +12y^2, chruser? cuz I got -12y^2. Everything else is the same, in different order.

for #1 i got

5. x = square root of 155xyi over 5 square root 15

:-/ il stick to algebra 2 >.<

dam LordZpider i wish i was as smart as you lol i look at your work and cant even follow it lol. and that freaks me out becuase i am in my schools highest math class lol are you in high school or college?

i wish i had brains like dat =-0

Well, obviously he cut out a shit load of steps. LordZpider, please write out your steps so we can follow it next time. I am fine up until you wrote 0 = "B L A H".... Then you basically solved it after that. Write your steps after that.

You definitely skipped a lot of steps, and there is no way anyone can just intuitively solve the way you did from that one step to the next...

Why did you even bother writing x^0?

Tidus, I'm in college as you can obviously tell in my sig.

Robot, the reason for writing x^0, cuz i'm afriad people might not follow that i put it in quadratic form.

And I'm going to write how to follow this...

Line 1->2: Long Division
Line 2->3: multiplied every element with (x-y)
Line 3->4: on the left side added; on the right side distribed
Line 4->5: put x on right side and use communitive property to group the first 2 terms
Line 5->6: subtracted y from both sides; x^0 = 1 so i multiply by 1, which doesn't change the answer; also reverse distrubted (is there a better way to say this?) x into 2y^2-x.
Line 6->7: Quadratic formula (Algebra I)
Line 7->8: distributed and simplified inside the root and the negative outside the root
Line 8->9: added

Oh if you guys need help with high school math up to about 2nd year college math(you only need math as an engineer or math major), i can TRY to help you. Being a nice guy and all...

Heh, if you did long division for step 1 -> 2, that was quite unnecessary. Just break up the numerator into x - y + 2y, then get to step 2.

Ahhh, didn't even notice Quadratic Formula.... I should have too.

Oh, and how did you justify my questions with "I'm in college, as you obviously tell from my sig,"? That makes no sense what-so-ever. I too am in my 4th year of college, and only 1 year away from getting my BS and MS in Power Engineering. Math is my strong point.

What i meant was that my signature has my college on it, what's power engineer? where are you at?

And speaking of things that don't make sense, "1 year away from getting BS and MS," you can't one year from BOTH, i mean you need your undergraduates degree to even go into grad school and get a MS.

Oh this isn't suppose to be offensive, tho proof-reading it, i realized it sounded sorta anal.

Power Engineering is a track of Electrical Engineering. I go to Drexel University, and they have a program that you must get accepted into and maintain 3.25 GPA to stay in that enables the student to graduate with a BS and MS in five years.

wow that's a really good program, i'm jealous