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Posted 2009-04-29, 11:10 PM in reply to Skurai's post starting "Exact angle? That's easy, dude, 90..."
funny thing, teacher told me i need to write down process, so i can't calculator my way to correct answers anymore, fuckkkkkk
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kyeruu is neither ape nor machine; has so far settled for the in-betweenkyeruu is neither ape nor machine; has so far settled for the in-between
 
 
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Posted 2009-04-30, 08:02 AM in reply to kyeruu's post starting "funny thing, teacher told me i need to..."
kyeruu said: [Goto]
funny thing, teacher told me i need to write down process, so i can't calculator my way to correct answers anymore, fuckkkkkk
I wasn't talking about this homework set but rather I was trying to give you some comfort for the future. What you've got is pretty easy anyways... all you have to do is memorize the unit circle and you've got it.

cos(60) = 1 - 2sin^2(30) // I'm assuming you meant sin^2 here

Well the cos(60) from the unit circle is 1/2, the sin(30) is also 1/2
1/2 = 1 - 2*(1/2)^2
1/2 = 1/2

or the one with cos(x) = 3/5
Since cosine is equal to adjacent/hypotenuse
adjacent = 3
hyp = 5
Applying pythagoream's theorem to a right triangle you get opposite to be 4
So the sin(x) = opposite/hyp = 4/5
tan(x) = opposite/adjacent = 4/3

The whole adj, hyp, and opp things you will just have to remember and later on down the road it becomes second nature

Cosine(theta) = adj/hyp = x/hyp
Sine(theta) = opp/hyp = y/hyp
Tangent(theta) = opp/adj = y/x

Since the sec, csc, and cot functions are just the inverse of their counterparts(and trust me rarely used except in computations), then you just invert the above fractions for their values... but really the easier way to think about it is sec(theta) = 1/cos(theta), and just let the algebra work it out.

So if you want the sec(60), then just take 1/cos(60) = 1/0.5 = 2
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S2 AM shows clear signs of ignorance and confidence; the two things needed to succeed in lifeS2 AM shows clear signs of ignorance and confidence; the two things needed to succeed in life
 
 
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Posted 2009-04-30, 08:10 AM in reply to S2 AM's post starting "I wasn't talking about this homework..."
You've really progressed since the Army days eh?
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Posted 2009-04-30, 08:54 AM in reply to Sum Yung Guy's post starting "You've really progressed since the Army..."
Sum Yung Guy said: [Goto]
You've really progressed since the Army days eh?
Lol I knew all that stuff in the army days, the army's just not interested in it. But I've learned, and I quote, a 'shitload' in my two years of college.
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S2 AM shows clear signs of ignorance and confidence; the two things needed to succeed in lifeS2 AM shows clear signs of ignorance and confidence; the two things needed to succeed in life
 
 
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Posted 2009-04-30, 10:43 AM in reply to S2 AM's post starting "Lol I knew all that stuff in the army..."
What school? Is the army paying?
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Grav never puts off to tomorrow what can be done the day after tomorrowGrav never puts off to tomorrow what can be done the day after tomorrowGrav never puts off to tomorrow what can be done the day after tomorrowGrav never puts off to tomorrow what can be done the day after tomorrowGrav never puts off to tomorrow what can be done the day after tomorrow
 
 
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Posted 2009-04-30, 12:14 PM in reply to Grav's post starting "What school? Is the army paying?"
Grav said: [Goto]
What school? Is the army paying?
VA Tech. Yes.
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Posted 2009-06-16, 03:30 PM in reply to Sum Yung Guy's post starting "VA Tech. Yes."
Sum Yung Guy said: [Goto]
VA Tech. Yes.
Cool.
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Grav never puts off to tomorrow what can be done the day after tomorrowGrav never puts off to tomorrow what can be done the day after tomorrowGrav never puts off to tomorrow what can be done the day after tomorrowGrav never puts off to tomorrow what can be done the day after tomorrowGrav never puts off to tomorrow what can be done the day after tomorrow
 
 
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Posted 2009-04-30, 10:47 AM in reply to S2 AM's post starting "I wasn't talking about this homework..."
Trig's pretty easy if you're in the class, but I can't remember a lot of it. I haven't had it in like 3 years at least.
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Posted 2009-06-16, 08:04 AM in reply to S2 AM's post starting "I wasn't talking about this homework..."
Bump! If they actually want you to find exact trigonometric values to n decimal places of "unit circle unfriendly" angles without a calculator, look into taylor series and fourier series. They converge fairly quickly, but it will still probably take, say, 5-10 minutes of number crunching for 5 decimal places even if you're fairly fast.
"Stephen Wolfram is the creator of Mathematica and is widely regarded as the most important innovator in scientific and technical computing today." - Stephen Wolfram

Last edited by Chruser; 2009-06-16 at 08:07 AM.
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Posted 2009-06-16, 08:07 AM in reply to Chruser's post starting "Bump! If they actually want you to find..."
Or use WolframAlpha to do all your homework.

http://www34.wolframalpha.com/input/...45(degrees)/52
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