Math challenge!

Try a double integral with polar coordinates.

Eight, sixteen, what's the difference?

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Not been taught double integration yet. In fact, I don't think I will be taught it unless I do Further Maths, or go on to Degree Level Maths.

Either way, it's not on the A-Level Mathematics syllabus.

At first glance every time I see this thread I read "Meth Challenge!"

Well, I'm going to go ahead and post the answer:

If you have the general equation: x = (a + b) cos(t) - b cos((a/b + 1)t), y = (a + b) sin(t) - b sin((a/b + 1)t) then area = pi*b^2(m^2 + m).

There's actually a pretty creative way using calculus to do it if anyone's interested. That's the one I was shooting for. Plugging it into a formula is no fun.

I'll get another one up soon.